y=9x/x^2+4x+4

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Solution for y=9x/x^2+4x+4 equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

y = 4*x+(9*x)/(x^2)+4 // - 4*x+(9*x)/(x^2)+4

y-(4*x)-((9*x)/(x^2))-4 = 0

y-4*x-9*x^-1-4 = 0

-4*x^1-9*x^-1-4*x^0 = 0

(-4*x^2-4*x^1-9*x^0)/(x^1) = 0 // * x^2

x^1*(-4*x^2-4*x^1-9*x^0) = 0

x^1

-4*x^2-4*x-9 = 0

-4*x^2-4*x-9 = 0

DELTA = (-4)^2-(-9*(-4)*4)

DELTA = -128

DELTA < 0

x in { } 

x belongs to the empty set

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